Different processes's environment variable map different memory addresses

[BBS-Bill-Gates]

Question

Hello, I'm glad to read you write up, give men a lot of inspiration. After read you 9th level write up, I find a problem.

• You get the mapped SHELLCODE address of the getenv process as the level9 process.

Prove

The first program(first.c)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char** argv){
	printf("hello, world\n");
	printf("%s => %p\n", argv[1], getenv(argv[1]));
	return 0;
}

The second program(second)

#include <stdlib.h>
#include <stdio.h>

int main(int argc, char *argv[]) {
    printf("%s => %p\n", argv[1], getenv(argv[1]));
    return 0;
}

Compile

gcc first.c -o first -m32
gcc second.c -o second -m32

Run

First

> ./first SHELLCODE
hello, world
SHELLCODE => 0xbffffd8d

Second

> ./second SHELLCODE
SHELLCODE => 0xbffffd8b

Summary

Different processes map the environment variable different memory addresses
The 9th Correct Write Up