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4 changes: 4 additions & 0 deletions contains-duplicate/8804who.py
Original file line number Diff line number Diff line change
@@ -0,0 +1,4 @@
class Solution:
def containsDuplicate(self, nums: List[int]) -> bool:
return len(set(nums)) != len(nums)

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한줄코딩 깔끔하네요  👍


14 changes: 14 additions & 0 deletions house-robber/8804who.py
Original file line number Diff line number Diff line change
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class Solution:
def rob(self, nums: List[int]) -> int:
if len(nums) == 1:
return nums[0]
elif len(nums) == 2:
return max(nums)
else:
nums = [0] + nums
dp = [0 for _ in range(len(nums))]
dp[1] = nums[1]
for i in range(1, len(nums)):
dp[i] = max(dp[i-2]+nums[i], dp[i-1])
return dp[-1]

19 changes: 19 additions & 0 deletions longest-consecutive-sequence/8804who.py
Original file line number Diff line number Diff line change
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class Solution:
def longestConsecutive(self, nums: List[int]) -> int:
num_set = set(nums)
answer = 0
while num_set:
num = num_set.pop()
l, r = 1, 1

while num - l in num_set:
num_set.remove(num-l)
l += 1

while num + r in num_set:
num_set.remove(num+r)
r += 1

answer = max(answer, l+r-1)
return answer

11 changes: 11 additions & 0 deletions top-k-frequent-elements/8804who.py
Original file line number Diff line number Diff line change
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class Solution:
def topKFrequent(self, nums: List[int], k: int) -> List[int]:
num_list = {}
for num in nums:
if num not in num_list:
num_list[num] = 1
else:
num_list[num] += 1

return [n[1] for n in sorted([[num_list[key], key] for key in num_list.keys()], reverse=True)[:k]]

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heapq.nlargest 사용을 고려할 수도 있을 것 같습니다!


8 changes: 8 additions & 0 deletions two-sum/8804who.py
Original file line number Diff line number Diff line change
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class Solution:
def twoSum(self, nums: List[int], target: int) -> List[int]:
num_list = {}
for i in range(len(nums)):
if target-nums[i] in num_list:
return [num_list[target-nums[i]], i]
num_list[nums[i]] = i