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Evan McCullough's solutions to the LetsDrill Challenge #115

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Evan McCullough's solutions to the LetsDrill Challenge
BIGred053 May 24, 2019
7660d12
Updated with the MUCH simpler min_by
BIGred053 May 24, 2019
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39 changes: 28 additions & 11 deletions letsdrill.rb
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Original file line number Diff line number Diff line change
@@ -1,24 +1,41 @@
def get_letter_grade(integer)

#Put your code here!

if integer > 89
'A'
elsif integer > 79 # Using just > here, since this elsif implies already being <= 89
'B'
elsif integer > 69 # Using just > here, since this elsif implies already being <= 79
'C'
elsif integer > 59
'D'
else
'F'
end
end

def shortest_string(array)

#Put your code here!
min_string = array.join
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@djlax805 djlax805 May 24, 2019 •
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@BIGred053 Take a look at the Ruby methods min or min_by and see if you can simplify this answer! Nice thought out solution though!

if min_string.length == 0
return nil
else
array.each do |str|
if str.length < min_string.length
min_string = str
end
end
return min_string
end

end



### Don't touch anything below this line ###

p "Fetch Letter Grade: You should have 2 trues"
p get_letter_grade(89) == "B"
p get_letter_grade(73) == "C"
p get_letter_grade(89) == "B"
p get_letter_grade(73) == "C"
p
p "Shortest String: You should have 3 trues"
p shortest_string(["touch","this", "car"]) == "car"
p shortest_string([]) == nil
p shortest_string(["can", "a", "solve", "Find", "solution"]) == "a"
p shortest_string([]) == nil
p shortest_string(["can", "a", "solve", "Find", "solution"]) == "a"