CC - 3

[ankitakulkarnigit]

No description provided.

[super30admin]

• Strengths:

  • The approach using a frequency map (Counter) is efficient and correctly handles both cases (k=0 and k>0).
  • The code is well-commented and easy to understand.
  • The time complexity is optimal for this problem.

• Areas for Improvement:

  • The use of the res list to store pairs is unnecessary and increases space complexity. You can maintain the count directly without storing the pairs.
  • The check for sorted([key+k,key]) not in res is inefficient. Since you are only checking key + k, you can avoid storing pairs altogether.
  • The print statement for res should be removed in the final solution as it is not required for the problem output.

• Suggested Optimization:

  • Remove the res list and directly increment the count when a valid pair is found. This will reduce space complexity and improve efficiency.